#2520 is the smallest number that can be divided 
#by each of the numbers from 1 to 10 without any remainder.

#What is the smallest number that is evenly 
#divisible by all of the numbers from 1 to 20

number = 0
found = False
#starting value of 20 x 19
# because we need a number which
# is both a multiple of 19 and 20
# and only numbers that are 
# multiples of 20 x 19 
# fullfill this requirement
curNum = 20 * 19
foundCur = False
#only need to check 20-11, because all 
#numbers 10-1 equally divide the numbers
#already in the list.
checknumbers = [20,19,18,17,16,15,14,13,12,11]

while not found:
	foundCur = True
	for i in checknumbers:
		if curNum % i > 0:
			foundCur = False
			break
	
	if foundCur:
		number = curNum
		found = True

	#only check multiples of 20 x 19
	# because no other numbers will
	# be multiples of both 20 and 19
	curNum += 20 * 19

print "The smallest number that can be evenly divided by the numbers 1-20 is %d " % (number,)